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1 year ago

A pebble is tossed into the air from the

Mathematics

1 answer:

Norma-Jean [14]1 year ago

6 0

Answer:

20 [ft].

Step-by-step explanation:

according to the equation of the height the related height is 20 [ft], when x=1.

All the details are provided in the attachment; the graph is shown with red curve line.

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The entire rectangle below has an area of .

Nastasia [14]

Answer:

Hence the required ans. Is 24cm2.

Step-by-step explanation:

I have explained Ans. at above. See it and how you Understand it. If you have any doubt then Comment . if you Like then Plz Give me 5 star rating

5 0

3 years ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o

krok68 [10]

Answer:

you need to convert pounds to kilograms. 196 pounds is 88.904 kilograms. The directions tell you that 20 milligrams of the drug is to be administered for each kilogram of a person's weight. Now you need to multiply 88.904 by 20. That should give you 1778.08 milligrams of lincomycin. You would then mix 250 cc's of saline solution to the 1778.08 milligrams of lincomycin; but I think its just asking you how much lincomycin to administer.

at what rate per minute should the 250 cc solution be adminstered

4 0

3 years ago

What is the equation of a line, in general form, that passes though points (-1,2) and (5,2)?

Tom [10]

Answer:

Step-by-step explanation:

To write the equation of the line. first calculate the slope using the slope formula.

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{2-2}{5--1}= \frac{0}{6} = 0$

Since the slope of this line is 0, it is horizontal and has the form y=b where b is the y-coordinate. So y = 2 is the equation. In general form, it would be y-2 = 0

3 0

3 years ago

If f(x) = 3x 7, find f(a - 1) a. 3a 6 b. 3a 4 c. 3a 8 d. 3a 10

Rom4ik [11]

Hello,

Let's suppose f(x)=3x+7
f(a-1)=3(a-1)+7=3a-3+7=3x+4
Answer B with a sign "++++++++++++++++++++++++++++"

5 0

3 years ago