All categories

3 years ago

Jeanette ice cream shop sold 10 sundaes with nuts and 7 sundaes without nuts to the total number of sundaes

Mathematics

2 answers:

Alecsey [184]3 years ago

6 0

The answer to the question is 17

NikAS [45]3 years ago

6 0

There are 10 sundaes with nuts, and 7 without nuts. Our task is to find the total number of sundaes. We can find this by adding 10 + 7. This gives us 17 sundaes.

You might be interested in

Three years from now Tom will be twice as old as Jean and two years ago the sum of their ages was 26. How old is Tom now?

Ber [7]

Answer:

Step-by-step explanation:

Tom'age: a

Jean'age: b

3+a=2(b+3)

a-2+b-2=26

a =2b+3

2b+3-2+b-2=26

a=2b+3

3b=27

a=21

b=9

8 0

3 years ago

Melissa’s birthday is next week and she has been receiving cards in the mail with different amounts of money. She has received 5

irga5000 [103]

The mean will stay the same
It will remain 25

5 0

3 years ago

The number of messages that arrive at a Web site is a Poisson distributed random variable with a mean of 6 messages per hour. Ro

QveST [7]

Answer:

a) There is a 16.0623% probability that 5 messages are received in 1 hour.

b) There is a 11.5880% probability that 10 messages are received in 1.5 hours.

c) There is a 22.4042% probability that 2 messages are received in 0.5 hours.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have a mean of 6 messages per hour.

(a) What is the probability that 5 messages are received in 1 hour?

Find the value of P when $x = 5$ and $\mu = 6$

$P(X = 5) = \frac{e^{-6}*(6)^{5}}{(5)!} = 0.160623$

There is a 16.0623% probability that 5 messages are received in 1 hour.

(b) What is the probability that 10 messages are received in 1.5 hours?

The mean is 6 messages in one hour.

For 1.5 hours, the mean is 6*1.5 = 9 messages.

We have to find the value of P when $x = 10$ and $\mu = 9$ .

$P(X = 10) = \frac{e^{-9}*(9)^{10}}{(10)!} = 0.115880$

There is a 11.5880% probability that 10 messages are received in 1.5 hours.

(c) What is the probability that less than 2 messages are received in 1/2 hour?

The mean is 6 messages in one hour.

For 0.5 hours, the mean is 6*0.5 = 3 messages.

We have to find the value of P when $x = 2$ and $\mu = 3$ .

$P(X = 10) = \frac{e^{-3}*(3)^{2}}{(2)!} = 0.224042$

There is a 22.4042% probability that 2 messages are received in 0.5 hours.

6 0

3 years ago

What a the advantages and disadvantages of investing your money in a Certificate of deposit rather than a regular savings accoun

Dominik [7]

Answer:

well obviously if you invest in something it could not work out, and you would lose your money, but if you invest and it is successful then you make not lose.

Step-by-step explanation:

3 0

3 years ago

______is a statistical method used to determine whether a relationship between variables exists.

Anika [276]

Answer:

correlation

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers