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Katyanochek1 [597]
1 year ago
9

How do you write complex fractions in Word?

Mathematics
1 answer:
PIT_PIT [208]1 year ago
6 0

The steps to writing complex fractions in Word are elaborated below.

Microsoft Word, a word-processor computer program propelled in 1983 by the Microsoft Corporation. Software engineers Richard Brodie and Charles Simonyi joined the Microsoft group in 1981, and in 1983 they discharged Multi-Tool Word for computers that ran an adaptation of the UNIX working framework. Afterward that year, the program was revamped to run on personal computers, such as the IBM PC, beneath Microsoft’s version.The steps to writing complex  fractions are, the first step is to switch to a fraction character, then click insert then click to symbols then go to symbols, in the subset drop-down list, then click number forms and select a fraction, the clicked insert then close.

To know more about complex fractions refer to the link brainly.com/question/14693420?referrer=searchResults.

#SPJ4

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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
HELP THIS IS DUE SOON!!!
aev [14]

Answer:

x≥9

Step-by-step explanation:

Pretend the Less than or equal to sign is just an equals sign

-7x+7=-56 Solve:

-7x=-56-7

-7x=-63

For the last step, if you divide a negative number, the Sign switches. So not the sign is greater than or equal to.

x>=9

6 0
3 years ago
I need help with this​
VLD [36.1K]

Answer:

im sorry wish i could

Step-by-step explanation:

4 0
3 years ago
Rachel has a bag of marbles. She added 6 marbles to the bag but then took out 8 marbles. The bag now has 14 marbles. How many ma
Anna35 [415]

Answer:

to my knowledge of this it is 28

Step-by-step explanation:

because just pay attention to the math in it she ended up with 14 in the end so add 14 and the 6 she added in the beginning and then you get 20 so then you add the 20 marbles and the 8 marbles she took out so you end up with 28 total marbles i hope this helps

6 0
3 years ago
Help I will make you a brainlist!!
enyata [817]
You answer would be Oy= 7x-1. I hope this helps!
4 0
3 years ago
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