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umka21 [38]
3 years ago
8

Noor rode her bike two fifth mile in one twelfth hour. At this rate, how far would Noor ride her bike in 1 hour?

Mathematics
2 answers:
Liula [17]3 years ago
8 0
2/5 in 1/12 of an hour

x in 1 hour

So multiply 12 to both fractions

2/5 x 12 in 1/12 x 12 of an hour

We get now:

24/5 in 1 hour

or:

4 4/5 in 1 hour


DENIUS [597]3 years ago
6 0
First convert 1/12 of an hour to minutes 1 hr= 60 minutes 1/12 x 60= 5 minutes ratio and proportion 2/5 / 5= x/60 cross multiply 5x= 24 x= 4 4/5 mi or 4.8 mi
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Ellen bought 5 6/8 pounds of grapes and 2 1/8 pounds of apples. How many pounds of fruit did she buy?
saveliy_v [14]
It is the grapes + apples= 5 6/8+2 1/8 = 46/8+ 17/8= 63/8 0r 7 7/8 pount of fruit.
4 0
3 years ago
[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd
Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 \frac{f(x+h)-f(x)}{h}

Now, for the purpose of the function, we need this:

Then we will have:

$$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

#SPJ1

6 0
1 year ago
Find the buying price of each of the following when 5% sales tax is added on the purchase of;
atroni [7]
1. 60 + 60*0.05 = 60 + 3 = 63;
2. 50 + 50*0.05 = 50 + 2.5 = 52.5;

7 0
3 years ago
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Need help with this question plz!!
mel-nik [20]

Let us consider the image on the left that is the image in which 1 and 2 , 3 and 4 are connected as image 1 and the other as image 2.

1. All Vertices are connected by the least amount of edges. True

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3.  Vertex 3 and 4 are not connected. This is false for image

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4. You can get to Vertex 1 from Vertex 4 by going through Vertex 3. This is true for image 1

5 0
3 years ago
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Y = x ^3 - 5x² +16x-80
Leokris [45]

Answer:

(x-5)(x^2+16)

3 0
3 years ago
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