All categories

3 years ago

I need help there is a stalker

Mathematics

1 answer:

stepan [7]3 years ago

3 0

Answer:

you really think anyone cares?

Step-by-step explanation:

Step 1- s t o p b e i n g a t r u m p i e

You might be interested in

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and

Sav [38]

Answer: Choice B

Building A; it is around 50.34 feet taller than building B

======================================================

Explanation:

Draw two right triangles such that they both have a reference angle of 40 degrees. Since it's an angle of elevation, place the angle near the horizontal side.

Opposite each reference angle is the height of the building, which we'll call h.

The adjacent side is the horizontal distance from the person to the building.

Building A is 120 ft away so it's height is...

tan(angle) = opposite/adjacent

tan(40) = h/120

h = 120*tan(40)

h = 100.69

This value is approximate. Make sure your calculator is in degree mode.

-----------------

Repeat the same idea for building B, except the adjacent side is smaller this time.

tan(angle) = opposite/adjacent

tan(40) = h/60

h = 60*tan(40)

h = 50.35

This value is approximate.

-----------------

Now subtract the heights

100.69 - 50.35 = 50.34

This shows that building A is roughly 50.34 taller than building B.

7 0

3 years ago

Read 2 more answers

Please help me with these thanks!! :)

solniwko [45]

Answer:

this one is rational and real :)

8 0

3 years ago

Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4

Art [367]

We are given polynomial function f(x)= $x^4-x^3-19x^2-x-20$

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

$x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)$

$\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.$

Grouping

$=\left(x^3-5x^2\right)+\left(x-5\right)$

Factoring out gcf from each group, we get

$=x^2\left(x-5\right)+\left(x-5\right)$

$=\left(x-5\right)\left(x^2+1\right)$

So, the final factored form of given polynomial will be

$x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)$

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

$x^2+1=0$

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

$x=\sqrt{-1}=$ + i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.

5 0

4 years ago

When two parallel lines are cut by a transversal, angles A and B are alternate interior angles that each measure 105°. What is t

Effectus [21]

Answer:

75°

Step-by-step explanation:

180 -105 = 75

3 0

3 years ago

Read 2 more answers

IS THIS GROWTH OR DECAY

Maksim231197 [3]

Answer:

It is a growth.

Step-by-step explanation:

If the number in parenthesis (exponential base) is greater than 1, then it is a growth. If it is between 1 and 0, then it is a decay.

4 0

4 years ago