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Sidana [21]
2 years ago
12

Consider the following points on cartesian plane. A (1;2) BC3; 1) and CG-3; 4) prove that Points A, B and C are collinear. ​

Mathematics
1 answer:
Arlecino [84]2 years ago
5 0

Step-by-step explanation:

Collinear points have the same gradient

find the gradient(slope) between AB first

= \frac{1 - 2}{3 - 1}  \\  =  \frac{ - 1}{2}

Find the one for BC

= \frac{4 - 1}{ - 3 - 3}  \\  =  \frac{3}{ - 6}  \\  =  \frac{ - 1}{2}

Find the gradient between AC now

=  \frac{4 - 2}{ - 3 - 1}  \\  =  \frac{2}{ - 4}  \\  =  \frac{ - 1}{2}

YOUR LAST STATEMENT NOW WILL BE

POINTS A,B AND C ARE COLLINEAR SINCE THE GRADIENTS BETWEEN THEM IS THE SAME!!!

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Answer:

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Step-by-step explanation:

Step 1: The surface area of  a cube = 6a^2, where "a" is the side of the cube.

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Step 3: Now plug in the surface area of the cube = 5400 and simplify.

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