I am in need of some help :(It looks so simple yet I don't get how to do it. Can anyone help explain?(picture of question attach
ed)source: Pearson/Savvas Realize
1 answer:
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Hi there!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =
= 43
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!