Following the rules of PEMDAS:
We would do exponents before the division
27 ^ 2 = 729
27 ^ 4 = 531,441
729/531441/3 = 0.000456247 approximately
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
Step-by-step explanation:
v=d/t, t=d/v, since t=t
1225/(v+w)=1100/(v-w)
1225v-1225w=1100v+1100w
2325w=125v
w=125v/2325, given v=575
w=125(575)/2325
w=30.91 mph
Answer:
115x-12x
Step-by-step explanation:
3(9-X) x 4+7
12(9-X)+7
108-12x +7
115-12x
Answer:
Slope in fraction form = -3/1
