Step-by-step explanation:
Change it into this
(2x-3)(2x-3)
Then multiply the insides and outsides and add them
(2x*2x) + (2x* -3) + (-3*2x) + (-3*-3)
Simplify
4x^2 - 6x -6x + 9
Simplify again
4x^2 - 12x + 9
The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.
The only two components in prime numbers are 1 and the number itself.
Any whole number greater than one is a prime number.
It has exactly two factors—1 and the actual number.
There is just one 2-digit even prime number.
Every pair of prime numbers is always a co-prime.
The product of prime numbers can be used to represent any number.
Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960
Learn more about prime numbers here:
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9514 1404 393
Answer:
(3, 1)
Step-by-step explanation:
We assume you want the solution to the system ...
The second equation gives a nice expression for x, so we can use that in the first equation.
2(y+2) -3y = 3 . . . . substitute for x in the first equation
2y +4 -3y = 3 . . . . . eliminate parentheses
-y = -1 . . . . . . . . . . . collect terms, subtract 4
y = 1 . . . . . . . . . . . . multiply by -1
x = 1 +2 = 3 . . . . . . substitute for y in the second equation
The solution is (x, y) = (3, 1).
Step 1: plug in the numbers. 7(6)-4
Step 2 multiply 7x6 42-4
Answer:31
Step-by-step explanation:
