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goldenfox [79]
3 years ago
15

Q # 4 Simplify the product

Mathematics
1 answer:
timama [110]3 years ago
8 0
For this case we have the following product:
 (x-4) (x + 3)

 We must use the distributive property correctly to solve the problem.
 We have then:
 x ^ 2 + 3x - 4x - 12

 Then, we must add similar terms.
 We have then:
 x ^ 2 - x - 12

 Answer:
 
The final product is given by:
 
x ^ 2 - x - 12

 option 2
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Simplify:<br>2a/3x+3a/2x+5a/6x​
xz_007 [3.2K]

Answer:

the answer is 10a+11x

Step-by-step explanation:

2a+3a+5a=10a

3x+2x+6x=11x

5 0
3 years ago
PLEAS HELP...FIRST CORRECT ANSWER WILL GET BRAINLIEST....PLEASE ANSWER NOW!!!!
dexar [7]

*a clearer picture containing the graph is shown in the attachment

Answer:

20% of the class earned a D

Step-by-step Explanation:

Step 1: Determine the total number of students represented on the graph:

9 students => D

5 students => C

14 students => B

17 students => A

Total number of students = 45

Step 2: Express each category of students who scored a particular grade as a fraction and as percentage.

9 students => D => \frac{9}{45} = \frac{1}{5} => as percentage, we have \frac{1}{5} * 100 = 20 percent

5 students => C => \frac{5}{45} = \frac{1}{9} => as percentage, we have \frac{1}{9} * 100 = 11.1 percent

14 students => B => \frac{14}{45} => as percentage, we have \frac{14}{45} * 100 = 31.1 percent

17 students => A => \frac{17}{45} => as percentage, we have \frac{17}{45} * 100 = 37.8 percent

Step 3: Check each statement to see if they are true or not based on the calculations above.

Statement 1: "⅕ of the students earned a C."

This is NOT TRUE From our calculation, ⅑ of the students earned a C.

Statement 2: "3% more students earned an A than a B." This is also NOT TRUE.

37.8% earned A, while 31.1% earned a B. Thus, about 6.7% more students earned an A than a B.

Statement 3: "20% of the class earned a D".  This is TRUE.

Check calculation in step 2.

Statement 4: "¼ of the class earned a B". This is NOT TRUE.

¼ is 25% of the class. Those who earned a B account for 31.1% not 25% (¼ of the class).

The correct statement is: "20% of the class earned a D"

7 0
3 years ago
The construction method used to construct a perpendicular through a point not on a line could also be used to construct a perpen
Rama09 [41]
The answer for the question above is TRUE.

Given a line segment with endpoints A and B, we must merely find a point on the perpendicular bisector of the line AB, then use the perpendicular line construction. To find the point on the perpendicular bisector, we must merely find a point that is equidistant from both A and B. We can do this with a compass by choosing a compass length greater than half the length AB, and then making an arc from A above the line AB. Then we make an arc from B having the same length. 

<span>Since we used the same length for each arc, the intersection of the arcs, P, is equidistant from A and B. Now we simply use the perpendicular line construction for line AB and P, which is off the line. This line will be a perpendicular bisector. </span>
6 0
3 years ago
Triangle MNP will be dilated according to the rule
KengaRu [80]

Answer: B (-2,6)

Step-by-step explanation:

I took the test

8 0
3 years ago
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If all students in the class voted, how many students are there in the class?
Paha777 [63]
All the ones that voted.
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4 years ago
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