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Leni [432]
1 year ago
15

a researcher is conducting a study on local businesses. in order to create her sample, she uses the yellowpages and a dice. she

rolls the dice, and, depending on the number rolled, counts that many businesses down in the list to call. what is her sampling frame?
Mathematics
1 answer:
katrin2010 [14]1 year ago
5 0

Her sample space is also the list of local businesses.

Sampling is a technique used in statistics when researchers choose a representative subset of a larger population and utilize that subset to carry out a study. Probability sampling and non-probability sampling are the two main types of sampling. Selecting the group from whom you will actually gather data for your study is the process of sampling. If you wanted to examine the perspectives of students at your university, for instance, you could interview a sample of 100 students. With the help of sampling, you can test a statistical hypothesis on the features of a population.

The yellow pages are used by the researcher to do research on neighborhood companies. As a result, her sample space also includes a list of nearby companies.  

Complete question: A researcher is conducting a study on local businesses. In order to create her sample, she uses the Yellowpages and a dice. She rolls the dice, and, depending on the number rolled, counts that many businesses down in the list to call. What is her sampling frame?

The list of local businesses in the Yellowpages.

All businesses within a $10 \mathrm{~km}$ radius.

The list of local businesses in the newspaper.

All businesses in the state she is located in.

The list of registered businesses in her area.

To read more about samplings, visit brainly.com/question/13287171

#SPJ4

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Answer:

5/6

Step-by-step explanation:

20 divide by 2 is 10

24 divide by 2 is 12

then have 10/12

10 divide by 2 is 5

12 divide by 2 is 6

answer is 5/6

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Louis built a swimming pool. The depth of the swimming pool is 5 feet. What is the volume of water that it will take to fill the
julia-pushkina [17]

Answer:

For a rectangular prism-like swimming pool: V = w\cdot l \cdot h. V = 360\,ft^{3} when h = 5\,ft, l = 12\,ft and w = 6\,ft.

Step-by-step explanation:

Let assume that swimming pool has a rectangular base and depth is the same  at any point at the bottom. In addition, let w and l be the width and length of the swimming pool. Then, the volume needed to fill the swimming pool is:

V = w\cdot l \cdot h, where h is the depth of the pool.

Let be h = 5\,ft, l = 12\,ft and w = 6\,ft. The volume of the swimming pool is:

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3 0
4 years ago
A window shaped like a parallelogram has an area of 23 4/5 square feet. The height of the window is 2 4/5 feet. How long is the
USPshnik [31]

Answer:

base = 8\frac{1}{2}ft

Step-by-step explanation:

The general formula for the area of a parallelogram is:

A = bh, where b = the length of the base and h = the height

Using the given values for area and height, we can solve for the missing variable of 'b':

23\frac{4}{5}=\frac{119}{5}

2\frac{4}{5}=\frac{14}{5}

\frac{119}{5}=\frac{14}{5}h

Multiply both sides by the reciprocal:

(\frac{5}{14})(\frac{119}{5})=(\frac{14}{5})(\frac{5}{14})h

\frac{119}{14}=h

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3 years ago
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
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