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3 years ago

7

Whats the difference between a sequence and a series?

1 answer:

snow_tiger [21]3 years ago

3 0

Answer:

A sequence is defined as an arrangement of numbers in a particular order. On the other hand a series is defiend as the sum of the elements of a sequence!

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Can somebody help me with this math question?

kap26 [50]

Answer:Hk and IJ

Step-by-step explanation:

They are parallel to eachother, hope this helped!

<!> Brainliest is appreciated! <!>

6 0

3 years ago

An office and apartment building is made up of modules. Each module is a rectangular prism. The building has 150 modules, and is

Elis [28]

Answer:

Part 1) 10 modules per floor

Part 2) Two different rectangular prism

Step-by-step explanation:

Part 1)

Let

x ----> the number of modules

y ---> the number of stories

we have

$x=150\ modules\\y=15\ stories$

Divide the number of modules by the number of stories

so

$\frac{x}{y}=\frac{150}{15}=10\ \frac{modules}{floor}$

Part 2) How many different rectangular prisms could be made from that number?

The number is 10

Look at the factors of 10

They are 1,2 ,4,5 and 10

Pick any two of these factors and determine if there is a third value from this list so that the product of the three factors is 10

There are 2 combinations that will work :

1 0×1×1

2 ×5×1

4 0

3 years ago

What is it called when a columns filled with pairs of numbers that have the same ratio?

Harman [31]

The answer is A ratio table.

3 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

How many times greater is the area of circle C than the area of circle A.

kicyunya [14]

Answer:

I need a picture

Step-by-step explanation:

sorry but without a picture i don't know wht to do

5 0

3 years ago