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givi [52]
1 year ago
12

I need to know, the area of sector AOB is what fractional part of the area of circle O

Mathematics
1 answer:
sertanlavr [38]1 year ago
6 0

We are given that triangle AOB

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What is 560 divided by 30? I need the answer as a mixed fraction.
Lesechka [4]
The answer down to its simplest for would be 56/3
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3 years ago
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How many solutions does the following equation have?<br> -4(+5) = -4- 20
Rus_ich [418]

Answer:

0

Step-by-step explanation:

Try looking at it in 2 ways- left side and right side. On the left side we have -4*5, which equals -20. On the right we have -4-20, which equals -24. so then when we add it all together (not literally) we get -20=-24. Since -20 and -24 obviously do not equal eachother, there is no solution.

4 0
3 years ago
The_________states that the sum measures of the interior angles of a triangle is 180​
serious [3.7K]

The Triangle sum theorem states that the sum measures of the interior angles of a triangle is 180 degree

<em><u>Solution:</u></em>

We know that,  

The Triangle Sum Theorem states that if you add all three interior angles, those are the angles inside the triangle, they would always add up to 180 degrees.

It is easy to remember that we add the three angle measurements to get 180 degrees because of the word sum in the name of the theorem. To make it short and sweet:

Consider a triangle with interior angles a, b, and c. Then we can say,

\angle a+\angle b+\angle c=180^{\circ}

The Triangle Sum Theorem is also called the Triangle Angle Sum Theorem or Angle Sum Theorem

7 0
3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
Cos/1+Sin = 1-Sin/Cos
ValentinkaMS [17]

Answer:

if you are asking for true or false it would be false

Step-by-step explanation:

6 0
3 years ago
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