Answer:
293; 869; 11 years
Step-by-step explanation:
N: no. of frogs
t: no. of years
N = 100(1.24^t)
N = 100(1.24⁵)
= 293
N = 100(1.24¹⁰)
= 859
1000 = 100(1.24^t)
10 = 1.24^t
lg10 = t×lg1.24
t = 1/lg1.24
t = 10.7 = 11 years
Answer: 100
5
Step-by-step explanation:
a) The mean of a normal distribution is also the median. Half the population will have values above the mean. Half of 200 is 100, so ...
... 100 students will have grades above 70%.
b) 84% is 14% above the mean. Each 7% is 1 standard deviation, so 14% is 2 standard deviations above the mean. The empirical rule tells you 95% of the population is within 2 standard deviations of the mean, so about 5% of students (10 students) got grades higher than 84% or lower than 56%. The normal distribution is symmetrical, so we expect about 5 students in each range.
... about 5 students will have grades above 84%.
Answer:
91.125 or 729/8
Step-by-step explanation:
take 4.5^3 to get 91.125
The answer is no solution, if my math is correct.
