Question

⦁ To the nearest tenth, find the perimeter of ∆ABC with vertices A(2,4), B(-2,1) and C(2,1). Show your work.

Answer 1

We need the length of the sides.
AB=√(2-(-2))²+(4-1)²=√16+9=√25=5; BC=√4²+0=4; CA=√0+9=3. AB+BC+CA=5+4+3=12.