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2 years ago

(DESPERATE PLEASE HURRY) question down below please show the work

Mathematics

1 answer:

Vlad1618 [11]2 years ago

6 0

Answer:

This is my second time answering one of your questions, chill out, just learn.

-46

Step-by-step explanation:

-46+17=-29

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Suppose you buy a CD for $300 that earns 3% APR and is compounded quarterly. The CD matures in 3 years. How much will this CD be

andrew-mc [135]

Given: Principal Amount (P) = $300

The rate of interest (r) = (3/4) compounded quarterly.

No. quarters in 3 years (n) = 3×4 = 12

To find: The amount for the CD on maturity. Let it will be (A)

Formula: Compound Amount (A) = P [ 1 + (r ÷100)]ⁿ

Now, (A) = P [ 1 + (r ÷100)]ⁿ

or, = $300 [ 1 + (3 ÷400)]¹²

or, = $300 × [ 403 ÷ 400]¹²

or, = $300 × 1.0938069

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What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0

Free_Kalibri [48]

Answer:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

Hence, ption B is true.

Step-by-step explanation:

Given the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

solving the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$\sqrt{x^2y^3}=xy\sqrt{y}$

$2\sqrt{x^3y^4}=2xy^2\sqrt{x}$

so the expression becomes

$\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$

Group like terms

$=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}$

Add similar elements

$=2xy^2\sqrt{x}+2xy\sqrt{y}$

Therefore, we conclude that:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

Hence, option B is true.

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Answer:

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Step-by-step explanation:

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