Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
The answer to the question is 23.
Answer: Could you check if you can make the question more visible?
Step-by-step explanation:
Tile:
<h2>See the explanation.</h2>
Step-by-step explanation:
(a)
There were total 5 men wearing coats.
5 coats can be returned to 5 men in 5! = 120 ways.
The coats can be returned to the accurate persons only in 1 way.
Hence, the probability that each man gets the correct coat is 
.
(b)
At the time of returning the first coat, the hostess will have 5 choices and for the second she will have 4 choices.
Hence, in 
ways the hostess can return the 2 coats.
There is only 1 possible case that each of the coats will return to the correct owner.
Hence, the required probability is 
.
