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11 months ago

Rewrite y + 1 = -2x – 3 in standard form

Mathematics

1 answer:

Misha Larkins [42]11 months ago

7 0

The algebraic expressions can be written as

$a+b+c=0$

The given expression is,

$\begin{gathered} y+1=-2x-3 \\ -2x-y=1+3 \\ -2x-y=4 \\ -2x-y-4=0 \\ 2x+y+4=0 \end{gathered}$

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A company produces alarm clocks. During the regular workweek, the labor cost for producing one clock is $4.00

Dmitrij [34]

Answer:

The question is not complete, nut here is the complete question ; A company produces alarm clocks. During the regular workweek, the labor cost for producing one clock is $4.00. However, if a clock is produced on overtime, the labor cost is $5.00. Management has decided to spend no more than a total of $51,000 per week for labor. The company must produce 12,000 clocks this week. What is the minimum number of clocks that must be produced during the regular workweek?

Step-by-step explanation:

Tthe detailed analysis and step by step calculation is as shown in the attached file.

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3 years ago

What are compatible numbers?

posledela

Numbers that are close in value to the actual numbers.

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2 years ago

Read 2 more answers

In a one-way ANOVA, what is the difference between the among-groups variance MSA and the within-groups variance MSW?

LuckyWell [14K]

Answer:

$MSR=MSA=\frac{SSR}{k-1}$

And $MSE=MSW=\frac{SSE}{N-k}$

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $j$ groups and on each group from $j=1,\dots,j$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}=6750+8000=14750$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1$ where k represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-k$ .

And the total degrees of freedom would be $df=N-1$

We can find the $MSR=MSA=\frac{SSR}{k-1}$

And $MSE=MSW=\frac{SSE}{N-k}$

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

And the we can find the F statistic $F=\frac{MSR}{MSE}=$