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Dmitrij [34]
1 year ago
15

Rewrite y + 1 = -2x – 3 in standard form

Mathematics
1 answer:
Misha Larkins [42]1 year ago
7 0

The algebraic expressions can be written as

a+b+c=0

The given expression is,

\begin{gathered} y+1=-2x-3 \\ -2x-y=1+3 \\ -2x-y=4 \\ -2x-y-4=0 \\ 2x+y+4=0 \end{gathered}

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Simplify and write the trig expression in terms of sin and cos
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We have:

cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}

We clear f(x):

f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}

we simply what we can:

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