2y-x=3/4(-y+1)first distribute
2y-x=-3/4y+3/4 get the y on one side
2y-x+3/4y=3/4 add 3/4y to both sides
2y+3/4y=3/4+x add x to both sides
11/4y=3/4+x now divide by 11/4 (both sides)
y=3/11+4/11x
y=3+4x/11
choice c is the answer
A cross section is the two dimensional shape that is created when a slice is made through a solid figure by an intersection of a plane and the solid body.
A square pyramid is a pyramid with a square base.
Case 1: When the plane intersects the square pyramid at an angle perpendicular to the base but not through the vertex. In this case a trapezoid is formed.
Case 2: When the plane intersects the square pyramid at an angle perpendicular to the base and through the vertex. In this case a triangle is formed.
Case 3: When the plane intersects the square pyramid at an angle parallel to the base. In this case a square is formed.
<span>Therefore, a
cross section made by the intersection of a plane and a square
pyramid at an angle either parallel or perpendicular to the base can be of shapes:
-square
-triangle
-trapezoid</span>
Answer:
250 nickles
Step-by-step explanation:
Nickles and dimes are coins with different currency values. One nickel(N) is equal to 5 cents while one dime(D) is equal to 10 cents. The ratio of nickel:dime is 5:7, to put into the equation it will be:
N/D= 5/7
7N=5D ---> 1st equation
There are 350 dimes, the equation will be:
D=350 ----> 2nd equation
We can find out the number of nickels by substitute the 2nd equation into the first. The calculation will be
7N=5D
N= 5D/7
N=5(350)/7
N= 250
Step-by-step explanation:
For this case we must find the product of the following expression:
![\sqrt [3] {5} * \sqrt {2}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5%7D%20%2A%20%5Csqrt%20%7B2%7D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
We rewrite the expression using the lowest common index of 6, then:
We rewrite the terms in an equivalent way:
We rewrite the expression using the property mentioned:
![\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%7D%20%2A%20%5Csqrt%20%5B6%5D%20%7B2%20%5E%203%7D%20%3D)
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So:
![\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}](https://tex.z-dn.net/?f=%5Csqrt%20%5B6%5D%20%7B5%20%5E%202%20%2A%202%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B6%5D%20%7B25%20%2A%208%7D%20%3D%5C%5C%5Csqrt%5B6%5D%7B200%7D)
ANswer:
Option b
