Answer:
1/14 Hope this helps!!! :) Have a great day
Step-by-step explanation:
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
The 12 sided cube with the numbers 1 to 12 is rolled. That means it can land on any number from 1 to 12. The number of total possible outcomes is 12. The number of favourable outcomes, that is, the number of times the cube lands on a number than 4 is 12-1=11.
Probability=Number of favourable outcomes/number of total possible outcomes
= 11/12
= 0.92
I really hope this helps! And pls mark it as brainliest.