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irina1246 [14]
3 years ago
11

Find the value of x in each of the following a) 5x + 1 = 11 b) 2x - 3 = 2

Mathematics
2 answers:
lesya [120]3 years ago
7 0

Answer:x=2, x=2.5

Step-by-step explanation:

5x+1=11

Subtract 1 from each side

5x=10

Divide each side by 5

x=2

2x-3=2

Add 3 to each side

2x=5

Divide each side by 2

x=2.5

Lynna [10]3 years ago
7 0

Answer:a)2 .(b) 2.5

Step-by-step explanation:

a) 5x + 1 = 11

Substract 1 from both sides

5x + 1 - 1 = 11 - 1

5x = 10

x = 10/5

x = 2.

b). 2x - 3 = 2

Add 3 to both sides

2x - 3 + 3 = 2 +3

2x = 5

x = 5/2

x = 2.5

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For Part A, you need to input x=6 into the equation 8x + 8 = 56 to see if 6 is a solution of that equation. It'll be 8(6) + 8 = 56 -> 48 + 8 = 56 -> 56 = 56. Does 56 equal 56? Then yes, x = 6 is a solution of the equation 8x + 8 = 56.

For Part B, it changed the value of x from 6 to 9. It also states that the left side of the equation (left side of the equal sign) stays the same so it'll still be 8x + 8. You do what you did in Part A, but instead of inputting 6, you do 9. It'll be like this: 8(9) + 8. It's asking how the right side would change, but that's basically asking what the answer is. If you do the math correctly, it'd be 72+8, which would be 80. The right side would need to be 80 if the solution is now x = 9.

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3 years ago
if the diameter of a circle is increased by 6 cm, what is the incriase in the circumference of the circle?​
dedylja [7]

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Step-by-step explanation:

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Read 2 more answers
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0
4 years ago
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