The answer is 24 (proof in picture below)
For Part A, you need to input x=6 into the equation 8x + 8 = 56 to see if 6 is a solution of that equation. It'll be 8(6) + 8 = 56 -> 48 + 8 = 56 -> 56 = 56. Does 56 equal 56? Then yes, x = 6 is a solution of the equation 8x + 8 = 56.
For Part B, it changed the value of x from 6 to 9. It also states that the left side of the equation (left side of the equal sign) stays the same so it'll still be 8x + 8. You do what you did in Part A, but instead of inputting 6, you do 9. It'll be like this: 8(9) + 8. It's asking how the right side would change, but that's basically asking what the answer is. If you do the math correctly, it'd be 72+8, which would be 80. The right side would need to be 80 if the solution is now x = 9.
Answer:
C=πd=π·6≈18.84956cm
Step-by-step explanation:
120 seconds
1 min = 60 seconds
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min