Question

Write an equation of a line passing through the point (4,-9) and parallel to the line 3x-6y=30

Answer 1

The equation of a line in the slope intercept form is expressed as

y = mx + c

Where

m represents slope

c represents y intercept

The equation of the given line is expressed as

3x - 6y = 30

Rearranging it so that it will look like the slope intercept form, it becomes

6y = 3x - 30

Dividing both sides by 6, it becomes

6y/6 = 3x/6 - 30/6

y = x/2 - 5

Looking at the equation, slope, m = 1/2

If two lines are parallel, it means that they have equal slope. This means that the slope of the line parallel to the given line is 1/2

To determine the y intercept, c of the line passing through the point (4, - 9), we would substitute

x = 4, y = - 9 and m = 1/2 into the slope intercept equation. It becomes

- 9 = 1/2 * 4 + c

- 9 = 2 + c

c = - 9 - 2

c = - 11

By substtuting m = 1/2 and c = - 11 into the slope intercept equation, the equation of the line would be

y = x/2 - 11