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3 years ago

Simplify the expression using properties of exponents. -16a-3b-5 2a-4b2

1 answer:

8 0

$a^n\cdot a^m=a^{n+m}\\\\-16a^{-3}b^{-5}\cdot2a^{-4}b^2=(-16\cdot2)(a^{-3}a^{-4})(b^{-5}b^2})\\\\=-32a^{-3+(-4)}b^{-5+2}=\boxed{-32a^{-7}b^{-3}}$

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How do I solve it I’m getting it wrong

k0ka [10]

Answer:

5). 2/3 divided by 1/2 answer is 1/6 and 6). 75cm and 2 3/4 times ...answer is 2.7x10-5 or ,2.7x10.5

Step-by-step explanation:

hope its help sana makatulong

6 0

2 years ago

The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your

umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

Sea tank looks like a rectangular prism,

Formula to calculate the volume of rectangular prism,

$Volume, V =whl$ .............................(1)

Where, w - Width of the rectangular prism

h - Height or depth of the rectangular prism

l - Length of the rectangular prism

From given,

w = 35 meters

l = 27 meters

h = 10 meters

Equation (1) becomes,

$V = (35)(10)(27)$

$= (945)(10)$

$=9450$

Volume of the sea tank, V = 9450 Cubic meters

Result:

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

3 0

3 years ago

Elimination method - -4x = 4y<br> 4x - 8y = 12

nika2105 [10]

Answer: (4,-4)

y=-4, x=4

Step-by-step explanation:

-4x=4y

4x-8y=12

-8y=-4x+12 Now I can substitute -4x for 4y

-8y=4y+12

-2y=y+12

-3y=12

y=-4

-4x=4y

-4x=4(-4)

x=4

6 0

3 years ago

Which graph represents the function y = cos(4x)?<br><br> Answer is graph B

VARVARA [1.3K]

Answer:

Step-by-step explanation:

Let the equation of the cosine function is,

y = Acos(Bx)

From the graph attached,

A = Amplitude = $\frac{1-(-1)}{2}$

= 1

B = $\frac{2\pi}{\text{Period}}$

B = $\frac{2\pi}{\frac{\pi}{2}-0}$

B = $\frac{4\pi}{\pi}$

B = 4

Therefore, equation of the cosine wave given in the graph will be,

y = 1.Cos(4x)

y = Cos(4x)

7 0

2 years ago

Read 2 more answers

Does anyone know the answer to this!?

PolarNik [594]

Answer:

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

$x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},$

where

$|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

So,

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

4 0

3 years ago