Simplify the expression using properties of exponents. -16a-3b-5 2a-4b2

1 answer:

8 0

$a^n\cdot a^m=a^{n+m}\\\\-16a^{-3}b^{-5}\cdot2a^{-4}b^2=(-16\cdot2)(a^{-3}a^{-4})(b^{-5}b^2})\\\\=-32a^{-3+(-4)}b^{-5+2}=\boxed{-32a^{-7}b^{-3}}$

You might be interested in

15 decreased by twice a number x in algebriac expression

postnew [5]

2x - 15

15 is decreased that is the key word here which indicates subtraction.

twice a number with given variable x is 2x

subtraction always goes behind so 2x - 15

4 0

3 years ago

A projector was sold after allowing 10% discount on the marked price and levying 13% VAT .If the selling price of the projector

Tom [10]

The marked price of the projector is $50,000.

<h3>What is the marked price?</h3>

The price of the projector after the discount can be represented with:

(100 - 10%)x - 90%x = 0.90x

Where x is the marked price

The price of the projector after the VAT is : (1.13) x 0.90x = 1.02x

Difference in price = 1.02x - 0.90x = 5850

0.12x = 5850

x = 5850 / 0.12

x = $50,000

To learn more about how to calculate discounts, please check: brainly.com/question/26061308

#SPJ1

8 0

1 year ago

Plz helppppppppppppppppppppppppppp

Zolol [24]

I think the answer is b

3 0

2 years ago

Ken normally leaves work at 5:00 pm, but he is leaving 20 minutes late today. He decides to make up time by taking the toll road

kobusy [5.1K]

Answer:

The correct answer is: $y=\frac{1}{3} x + 20$

Step-by-step explanation:

As stated in the question that x represents the number of minutes his normal commute takes. Here the keyword is normal; in the normal commute, Ken takes side streets instead of the toll road.

However, in this scenario, we have to come up with the equation that takes Ken's commute via toll road.

Ken can travel 3 times faster by taking the toll road (Given), which can be represented in the mathematical terms in terms of x as follows:

$x_{toll\_road}=\frac{1}{3}x$