The area of the shape is 230 cm.
2×2=4
4÷2=2
4+2=6
4+2+6=12
we know that,
put a number you like anything I will write x°
x°+12°=90°
90°-12°=78°,,
again,
78°-12°=66°,,
now,
remove 6° from 60°
60
-----
12
=5,,
The circumference of a circle of radius
is
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
So, in your case, the circumference is
![C=2\cdot \pi \cdot 21 = 42\pi](https://tex.z-dn.net/?f=C%3D2%5Ccdot%20%5Cpi%20%5Ccdot%2021%20%3D%2042%5Cpi)
The circumference is actually the length of the "perimeter", so the answer to questions 1 and 2 looks the same actually
45 million *
![2^{4}](https://tex.z-dn.net/?f=2%5E%7B4%7D)
= 45million * 16 = 720million
Or you can use
![y=Ae^{kt}](https://tex.z-dn.net/?f=y%3DAe%5E%7Bkt%7D)
A is equal to 45 million
To find the rate, k, we can plug in:
![90million=45million*e^{k*1} ](https://tex.z-dn.net/?f=90million%3D45million%2Ae%5E%7Bk%2A1%7D%0A)
![2=e^{k}](https://tex.z-dn.net/?f=2%3De%5E%7Bk%7D)
![k=ln(2)](https://tex.z-dn.net/?f=k%3Dln%282%29)
![y=4.5*10^{7}*e^{t *ln2}](https://tex.z-dn.net/?f=y%3D4.5%2A10%5E%7B7%7D%2Ae%5E%7Bt%20%2Aln2%7D)
Knowing that t = 4
![y = 4.5*10^{7}*e^{ln(2)*4} ](https://tex.z-dn.net/?f=y%20%3D%204.5%2A10%5E%7B7%7D%2Ae%5E%7Bln%282%29%2A4%7D%0A)