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1 year ago

Explain how websites are or are not credible

Business

1 answer:

Aleksandr-060686 [28]1 year ago

3 0

Answer:

- If a website includes a date and the name of the author who published it, it's most likely credible.

- If the end of a website has: ".gov" or ".org" that means they're credible.

Explanation:

Here are some questions to ask yourself when trying to find out if a website is credible or not:

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The role of a non-executive director

Reptile [31]

Answer:

Essentially the non-executive director's (NED) role is to provide a creative contribution to the board by providing independent oversight and constructive challenge to the executive directors. ... Clearly, it is appreciated that NEDs cannot give the same continuous attention to the business of the company.

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3 years ago

It is very easy to find papers on the internet/web and use them as my own.

Julli [10]

That is true,however; they are not your own and you are doing yourself a disservice. Grades aren't everything.

8 0

3 years ago

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by upper c equals 0.

Fantom [35]

Answer:

The cost per month is increasing at a rate $365.

Explanation:

Differentiation Formula

$\frac{d}{dx}(x^n)= nx^{n-1}$
$\frac{d}{dx}(a)=0$ [ where a is a constant]
$\frac{d}{dx}(ax^n)=a \frac{d}{dx}(x^n)= anx^{n-1}$

Given that,

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by

$c=0.2x^2+10,000$ .

Again given that,

the rate of changing production is 13 unit per month

i.e $\frac{dx}{dt}=13$

To find the cost per month, we need to find out the value $\frac{dc}{dt}$ when production is changing at the rate 13 units per month and the production is 70 units.

$c=0.2x^2+10,000$

Differentiating with respect to t

$\frac{d}{dt}(c)=\frac{d}{dt}(0.2x^2)+\frac{d}{dx}(10,000)$

$\Rightarrow \frac{dc}{dt}=0.2\frac{d}{dt}(x^2)+\frac{d}{dx}(10,000)$

$\Rightarrow \frac{dc}{dt}=0.2\times 2x^{2-1}\frac{dx}{dt}+0$

$\Rightarrow \frac{dc}{dt}=0.4x\frac{dx}{dt}$

Plugging $\frac{dx}{dt}=13$

$\Rightarrow \frac{dc}{dt}=0.4x\times 13$

$\Rightarrow \frac{dc}{dt}=5.2x$

$\frac{dc}{dt}|_{x=70}=5.2\times 70$ [ plugging x=70]

=364

[ The unit of c is not given. Assume that the unit of c is dollar.]

The cost per month is increasing at a rate $365.

4 0

3 years ago

Which of these is NOT an advantage of the impact of computer careers.

VMariaS [17]

<span>C.An increase in the number of stress and health concerns that result from working in a computer environment.</span>

7 0

3 years ago

Read 2 more answers

Computer equipment was acquired at the beginning of the year at a cost of $65,000 that has an estimated residual value of $3,800

Ivan

Answer:

a) Depreciable cost = $61,200

b) Straight-line rate = 12.5%

c) Annual depreciation for the straight-line rate is:

$7,650.

d) The double-declining balance depreciation amount for the 1st year is:

$15,300.

e) Journal Entry of sale of equipment at the end of the 4th year for $20,000, using the straight-line rate:

Debit Sale of Equipment $65,000

Credit Equipment $65,000

To record the transfer of the equipment account.

Debit Accumulated Depreciation $30,600

Credit Sale of Equipment $30,600

To record the transfer of accumulated depreciation to the account.

Debit Cash Account $20,000

Credit Sale of Equipment $20,000

To record the cash received from the sale.

Debit Profit and Loss Account $14,400

Credit Sales of Equipment $14,400

To record the loss on sale of equipment.

Explanation:

a) Data and Calculations:

Cost of computer equipment = $65,000

Estimated residual value = 3,800

Depreciable value = $61,200

Estimated useful life = 8 years

Annual depreciation expense = $7,650 ($61,200/8) or $61,200 * 12.5%

Depreciable cost = $61,200 ($65,000 - $3,800)

Straight-line rate = 12.5% (100%/8)

Double-declining rate = 12.5% x 2 = 25%

Depreciation amount for the 1st year = $15,300 ($61,200 * 25%)

Book value of asset at the end of the 4th year, straight-line method:

Cost of equipment = $65,000

Accumulated Depreciation = $30,600 ($7,650 * 4)

Book value = $34,400

Sales proceed = $20,000

Loss on sale of asset = $14,400 ($34,400 - $20,000)

4 0

3 years ago