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kogti [31]
1 year ago
8

I need help please quickly I need help10(2 + 3) - 8 · 3.​

Mathematics
2 answers:
Alekssandra [29.7K]1 year ago
8 0

Answer:

10(5)-24 ----) 50-24 -----) 26

Step-by-step explanation:

answe is 26

FinnZ [79.3K]1 year ago
3 0

20+50-8 times 3

70 -24

46 is answer

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Citrus2011 [14]
Hi there! 200 * 180 is 36,000. You can solve this problem by crossing out the 0's, bringing the down, and multiply 18 * 2 to get 36. The product is 36,000.
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F(x)=x^2-3x+18 how many distinct real number zeros does f have?
vampirchik [111]

Answer:

None of the distinct real number zeros the function have.

Step-by-step explanation:

Considering the function

f(x)=x^2-3x+18

The zeroes of a function are those values that touches the x-axis. In order to find those values we must

Set  f(x) = 0 in order to find those values

0=x^2-3x+18

\mathrm{Switch\:sides}

x^2-3x+18=0

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=18:\quad x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{-\left(-3\right)+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

As

3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}=3+\sqrt{63}i

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x=\frac{3+\sqrt{63}i}{2\cdot \:1}

x=\frac{3+3\sqrt{7}i}{2}

x=\frac{3}{2}+\frac{3\sqrt{7}}{2}i

Similarly,

x=\frac{-\left(-3\right)-\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}:\quad \frac{3}{2}-i\frac{3\sqrt{7}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3}{2}+i\frac{3\sqrt{7}}{2},\:x=\frac{3}{2}-i\frac{3\sqrt{7}}{2}

BUT, NONE OF THEM ARE REAL NUMBER ZEROS.

Therefore, none of the distinct real number zeros the function have.

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