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8 months ago

The value of a certain stock tripled. If you knew what the stock used to be worth, how would you find how much it is

Mathematics

1 answer:

SpyIntel [72]8 months ago

5 0

Take the amount that it first was and multiple by 3…..?

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The perimeter of a rectangular sandbox is 34 feet if the length of the sandbox is 8 feet what is the width of the sandbox

MrRa [10]

L= length
W= width

Perimeter= 2L + 2W

substitute the known numbers
34 ft= 2(8 ft) + 2W

34= 16 + 2W
subtract 16 from both sides

18= 2W
divide both sides by 2

9 ft= W

ANSWER: The width is 9 feet.

Hope this helps! :)

8 0

2 years ago

Read 2 more answers

Solve for the inequality x / 3 < -7

Aneli [31]

Answer:

$x < - 21$

Step-by-step explanation:

1. Multiply both sides by 3.

$x < - 7 \times 3$

2. Simplify 3 × 7 to 21.

$x < - 21$

therefor, the answer is x < -21

3 0

2 years ago

The scatter plot shows the results of a survey in which 10 people were asked how many e-mail accounts and how many credit cards

kakasveta [241]

Answer:

A person with 7 credit cards has 5 credit cards

4 0

2 years ago

What is the decimal conversion of 8 39/40 and does the decimal repeat or terminate

bulgar [2K]

839/40 = 20.975
Scientifically speaking in numbers there is no termination existing numbers are round of but technically speaking it TERMINATES

3 0

2 years ago

I need help, pls !!!

luda_lava [24]

Answer:

D) 11.2 Orange

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (-8, -1)

Point (-3, 9)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute [DF]: $\displaystyle d = \sqrt{(-3+8)^2+(9+1)^2}$
Add: $\displaystyle d = \sqrt{(5)^2+(10)^2}$
Exponents: $\displaystyle d = \sqrt{25+100}$
Add: $\displaystyle d = \sqrt{125}$
Simplify: $\displaystyle d = 5\sqrt{5}$
Evaluate: $\displaystyle d = 11.1803$
Round: $\displaystyle d = 11.2$

8 0

2 years ago