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9 months ago

The value of a certain stock tripled. If you knew what the stock used to be worth, how would you find how much it is

Mathematics

1 answer:

SpyIntel [72]9 months ago

5 0

Take the amount that it first was and multiple by 3…..?

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ikadub [295]

The dependent is the childrens hospital

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2 years ago

Please help me out ‼️

Westkost [7]

Answer:

Step-by-step explanation:

In similar triangles, corresponding elements are proportional. Then we get,

(2x + 1)/(x-1) = 10/4

4(2x +1) = 10(x-1)

8x + 4 = 10x - 10

8x = 10x - 14

2x = 14

x = 7

Hope it helps and if it does, please mark me brainliest...

6 0

3 years ago

Read 2 more answers

Find the area of each figure.

grandymaker [24]

Answer: if thats a ten then its

Step-by-step explanation:

rectangle is LxW= 70

triangle is A=h(b)/b = 17.5

together it would be 87.5

i think lol

8 0

2 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

5 0

3 years ago

A total amount of $30 was placed in 4 envelopes, a different amount in each one. Money from the largest share was taken to doubl

Triss [41]

It is about 7.5 divide 30 by 4

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2 years ago