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Nostrana [21]
1 year ago
15

MathA single die is rolled. Find the odds in favor of rolling a number greater than 3.The odds in favor of rolling a number grea

ter than 3 are 0:0. (Simplify your answers.)tentsccess
Mathematics
1 answer:
tamaranim1 [39]1 year ago
6 0

we have that

a number greater than 3

possible favorable results are

4, 5, 6

Probability that the event occur=3/6

Proba

You might be interested in
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
What is the mode? 22, 7, 22, 1, 7, 18, 18, 16, 6, 6, 7
kolbaska11 [484]

Answer:

7

Step-by-step explanation:

Put them in L to G

1 6 6 7 7 7 16 18 18 22 22

and u see how many times 7 repeated den all numbers.

3 0
3 years ago
Read 2 more answers
What are the main properties of a rectangle <br> Use rectangle (BCDE) to help you .
OleMash [197]

Answer:

it must be number 1

I am sure about parallel side and 4 right angles

6 0
3 years ago
2-1 help anyone pls............
ValentinkaMS [17]

Answer:

In what book?

Step-by-step explanation:

3 0
3 years ago
(1.)What is the value of 35−3m , when m = 4?
Len [333]
(1.) 35-3m
m= 4

35-3m
= 35-3(4)
= 35-12 (do the multiple/division first before doing the addition/subtraction)
= 23

C. 23

(2.) 1 + x ÷ 5
x = 80

1 + x ÷ 5
= 1+80÷5
= 1+16
= 17

(3.) mx-y
m=5, x=3, and y=8

mx-y
= 5(3)-8
= 15-8
= 7

(4.) 3a+15+bc−6
a=7, b=3, and c=15

3a+15+bc-6
= 3(7)+15+3(15)-6
= 21+15+45-6
= 75
4 0
4 years ago
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