A) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
<span>I choose one senior: r = 1
</span>
nCr = n! / (r! (n - r)!)
5C1 = 5! / (1! (5 - 1)!)
= (5 * 4 * 3 * 2 * 1) / (1 * 4!)
= 120 / (4 * 3 * 2 * 1)
= 120 / 24
= 5
b) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose two seniors: r = 2
nCr = n! / (r! (n - r)!)
5C2 = 5! / (2! (5 - 2)!)
= (5 * 4 * 3 * 2 * 1) / ((2 * 1) * 3!)
= 120 / (2 * (3 * 2 * 1))
= 120 / (2 * 6)
= 120 / 12
= 10
c) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose three seniors: r = 3
nCr = n! / (r! (n - r)!)
5C3 = 5! / (3! (5 - 3)!)
= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * 2!)
= 120 / (6 * (2 * 1))
= 120 / (6 * 2)
= 120 / 12
= 10
d) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose four seniors: r = 4
nCr = n! / (r! (n - r)!)
5C4 = 5! / (4! (5 - 4)!)
= (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1!)
= 120 / (24 * 1)
= 120 / 24
= 5
e) The answer is 1.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose five seniors: r = 5
nCr = n! / (r! (n - r)!)
5C5 = 5! / (5! (5 - 5)!)
= (5 * 4 * 3 * 2 * 1) / ((5 * 4 * 3 * 2 * 1) * 1!)
= 120 / (120 * 1)
= 120 / 120
= 1
Technical issues is the correct answer. This is because it causes problems in the company/business. Hope this helps
Answer:
You need to put the link on which is like the paper clip before you post.
Step-by-step explanation:
Answer:
32.6
Step-by-step explanation:
when you plug in for s and r you will get 66-33.4 since 5.5 multiped by 12 is 66 and 8.35 multiplied by 4 is 33.4 .
then you subtract them and that's how you'll get your answer
