E^2x -2e^x -8=0 => e<span>^(2x) -2e^x -8=0
Temporarily replace e^x with y.
Then (y)^2 - 2y - 8 = 0. Factors are (y-4) and (y+2).
Roots are y = 4 and y= -2.
Now remembering that we temporarily replaced e^x with y, we let
y=4 = e^x. We need to solve for x. Taking the natural log of both sides, we get:
ln 4 = x (answer)
We have to discard the other root (y= -2), because we cannot take the ln of a negative number.
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C: is the speed of light (3*10^8 m/s) and it is squared (raised to the power 2) in this equation.
Log[8/(36*3)]
Log[2/27]
Hope I really help you !
32. The absolute value of a number x (|x|) will always be positive. It just means how far the number is from 0 on the number line.
Answer:
5x²√2
Step-by-step explanation:
√50
The <em>square root of x^4 is x²</em>.
The <em>square root of 50 is 5√2</em>.
Multiplying those two gives us 5x²√2
