1. A box of fruit has 12 plums and 15 bananas. The
2 answers:
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Answer:
0.762 = 76.2% probability that this shipment is accepted
Step-by-step explanation:
For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17 randomly selected pens
This means that
(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)
This is when
. So
0.762 = 76.2% probability that this shipment is accepted
Answer:
4.9%
Step-by-step explanation:
This question is incomplete. However; it can be found on search engines. The complete question is as follows :
An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.
Solution :
In an ice chest there are different cans of juice. Among them
Number of cans of apple juice = 6
Number of cans of grape juice = 8
Number of cans of orange juice = 4
Number of cans of mango juice = 2
Total number of cans of juice = 6 + 8 + 4 + 2 = 20
Let A, B and C are the event of selecting of three cans. The events A, B and C are dependent.
Probability of selecting three cans of juice
P =
P (A) =
P (B) =
P (B) =
P = ×
×
=
= 0.049 or 4.9%
Probability of selecting three cans of grape juice is 4.9%