In Rome, do as the Romans do.
The vertical distance between the roofs of the two buildings is 150 meters. Let’s use the equation below to determine the time required for the bag to drop 150 meters.
d = vi * t + ½ * 9.8 * t^2, d = 150 m
Since the bag is thrown horizontally, the initial vertical velocity is 0 m/s.
150 = ½ * 9.8 * t^2, t = √(150/4.9) ≈ 5.53 seconds
We can use the time to determine the minimum horizontal velocity required for the bag to travel 20 meters.
v = 20 ÷ √(150/4.9) ≈ 3.61 m/s
Since this velocity is less than 5 m/s. I believe that the bag to accused could throw the bag to the accomplice. I would advise the prosecuting attorney to do some pleas bargaining to get the accused the best deal possible. The accused is GUILTY!
