Question

A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute. How much power is needed for the elevator’s trip?

Answer 1

A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute is 12500 W (12.5 kW).

What is Power?

Power is the amount of work that is done per unit of time. It can be associated with the speed of a change of energy within a system, or the time it takes to perform a job.

There are different types of power,

Mechanical power: is that work performed by an individual or a machine in a certain period of time.

Electric power: which is the result of the multiplication of the potential difference between the ends of a load and the current flowing there.

P= W/t

Where, P- Power,

W- Work

T- Time

The total weight of the passenger + elevator is

Fg = 500+24500

    = 25000

The total work done to rise the elevator + passenger is equal to the product between the total weight and the distance covered during the trip (d = 30 m):

W = Fgd

   = 25000×30

   =7,50,000 J.

The power needed for the trip is equal to the ratio between the work done (W) and the time taken (t):

P = W/t

Since the time taken is t = 1 min = 60 s, the power needed is

P = 750000 / 60

   = 12,500 W

P = 12.5 kW

Thus, Power was calculated as P = 12.5 kW.

Learn more about Power,

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