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lawyer [7]
3 years ago
7

Which is a characteristic of projectile motion?

Physics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0
<h2>Right answer: It follows a curved path </h2>

The movement of a projectile is a movement in two dimensions (forming a curved path: a parabola shape) with <u>constant acceleration. </u>

<u> </u>

A projectile is any body or object that is thrown or projected by means of some force and continues in motion by its own inertia. This means the only force that acts on it while in motion is <u>the acceleration of gravity</u> (in this case we are on Earth, so the gravity value is 9.8\frac{m}{s^{2}}).  

Where gravity influences the <u>vertical movement</u> of the projectile, while <u>the horizontal movement</u> of the projectile is the result of the tendency of any object to remain in motion at a constant speed (according to Newton's 1st law of motion sometimes called Law of Inertia).

The other options are <u>incorrect</u> because are <u>false</u>:

-The forward motion negates air resistance: There is always at least a small percent of air resistance, as long as that movement is done on Earth.  

-It has variable acceleration: In projectile motion acceleration is constant (gravity acceleration) .

-It is unaffected by gravity: The only force that acts on the projectile is due gravity.


Oksana_A [137]3 years ago
4 0

it follows a curved path

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Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will
denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

                 W_{net} = \Delta K

Also,   \Delta K = K_{initial} - K_{final}

                        = (0 - 4.0 \times 10^{-17}) J

                        = -4.0 \times 10^{-17} J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

                w = -Fd

       -4.0 \times 10^{-17} J = -F \times 0.3 m

                F = 1.33 \times 10^{-16}  

Therefore, relation between electric field and force is as follows.

              E = \frac{F}{q}

                 = \frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}

                 = 0.831 \times 10^{3} C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is 0.831 \times 10^{3} C.

3 0
4 years ago
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr
MakcuM [25]

Answer: current I is 144amp(A)

Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

F/L = permeability of space* I²/2*pi*r

Permeability of free space is 1.257*EXP {-6} Henry/meter

F/L is 0.244 N/m, pi is 3.142,

r is 1.7cm which is equal to 0.017meter.

I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

After cross multiplying and making I² subject of formula we have,

0.0261/(1.257*EXP {-6}) = I²

I = √{20736.7} =144ampere(A)

That means in each of the jumper wire there is 144amp(A)

8 0
3 years ago
A object is 200 miles from the center of a circle and makes a circuit every 2 hours. How fast is it moving?
Tanya [424]

Answer: 628.31 miles/h

Explanation:

The equation to calculate the average speed s of an object moving in a circular path is:

s=\frac{2 \pi r}{T} (1)

Where:

r=200 miles is the radius of the circumference

T=\frac{1}{f} is the period, which has an inverse relation with the frequency f=\frac{1 circuit}{2 h}=0.5 h^{-1}. Then T=\frac{1}{0.5 h^{-1}}=2 h

Solving the equation:

s=\frac{2 \pi (200 miles)}{2 h} (2)

s=628.31 miles/h (3)

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3 years ago
Rusty Pickins, a gold miner, has just found a chunk of gold. Rusty would like to change the gold from a solid to a liquid, so th
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<span>b.) Add heat to increase the molecular motion of the atoms</span>
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If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 96 ft/sec, then what is the maximum h
masya89 [10]
The height function would be s(t) = -16t^2 + 64t + 32.

Maximum height ---> set s'(t) = 0.

-32t + 64 = 0. ---> t = 2. s(2) = -16(2)^2 + 64(2) + 32 = the maximum height is 96 feet.

To find the velocity when it hits the ground, set s(t) = 0.

-16t^2 + 64t + 32 = 0. Divide by -16.

t^2 - 4t - 2 = 0. The only positive solution is x = 4.45.

s'(4.45) = -32(4.45) + 64 = It's going -78.4 feet/second when it hits the ground.
5 0
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