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tiny-mole [99]
3 years ago
10

The weather is warm and dry. Which change would a cold front bring?

Physics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

im prob too late lol but the answer would be rain or thunderstorms

Explanation:

i took the test :p

andreev551 [17]3 years ago
3 0

Answer:

rain or thunder

Explanation:

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A ball is thrown straight upward with a speed of 36 m/s. How long does it take to return to its starting point, assuming negligi
svetoff [14.1K]

Answer:

The time taken for the ball to return to the starting point is is 7.4 s

Explanation:

Given;

initial velocity of the ball, u = 36 m/s

the final vellocity at maximum height, v = 0

let time taken for the ball to reach maxmimum height = t

Time taken for the ball to return to the starting point is known as time of flight, calculated as;

t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}

T = (2 x 36) / 9.8

T = 7.4 s

Therefore, the time taken for the ball to return to the starting point is is 7.4 s

4 0
4 years ago
The lightest and heaviest flying birds are the bee hummingbird of Cuba, which weighs about 1.6 grams, and the great bustard of E
VMariaS [17]

Answer:

for the birds to be able to stay vertical in flight without falling down to earth, they must produce a lift that will counteract their weight

for the small bee humming bird,

mass = 1.6 g = 1.6 x 10^{-3}  kg

weight of the bird under acceleration due to gravity = mg

where g = acceleration due to gravity = 9.81 m/s^2

weight of the bird = 1.6 x 10^{-3}  x 9.806 = 0.0156 ≅ 0.016 N

for this bird to maintain flight, the least lift upward, it must generate must be equal to its weight downwards, i.e

lift = weight

therefore,

lift = <em>0.016 N</em>

<em></em>

For the bustard of Europe and Asia,

mass = 21 kg

weight of the bird under acceleration due to gravity = mg

weight of the bird = 21 x 9.806 = 205.9 N

lift = weight =  <em>205.9 N</em>

<em></em>

<em>lift generated is proportional to the wing surface area according to the lift equation</em>

L = Cs x p x \frac{v}{2} x S

where L = lift

C = lift coefficient

p = density of air

v = relative velocity of bird and air

S = surface are of the wing.

<em>The great bustard will have a proportionally larger wing area to hold its weight in flight</em>

<em></em>

7 0
3 years ago
A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th
Vesna [10]

Answer:

Average speed of car will be 48 km/hr  

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance t_1=\frac{d}{40}hr

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance t_2=\frac{d}{60}hr

So total time to cover 2d distance t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}

Average speed is the ratio of total distance to total time

So average speed =\frac{2d}{\frac{5d}{120}}=48km/hr

So average speed of car will be 48 km/hr

4 0
3 years ago
A 40-kg worker climbs a ladder upwards for 15m. What work was done during their climb upwards?
Bingel [31]

Answer:

Explanation:

The work increased the potential energy

W = PE = mgh = 40(9.8)(15) = 5880 J(oules)

4 0
2 years ago
A microstate is a state of a physical system described at the finest level of detail. A macrostate is a state of a physical syst
podryga [215]

Answer:

a. A list of the names of each student present today. (microstate)

b. The number of students in attendance. (macrostate)

Explanation:

You can fins the answer to this question by comparing the situation of the problem with a system of molecules with discrete energy.

Without importance of which molecules have a specific energy, but rather, what is the total amount of energy, you can get for different configurations of energy the same amount of the total energy. If different configurations of the energies of the molecules give you the same total energy of the system, you say that the macrostate is the same. In the case of the classroom, it does not matter how are distributed the students in the class, the total number of students is always the same. The macrostate is the same for what ever organization of the students in the class.

If you would interested in the energy of each molecules, you will obtain different configurations. In the case of the classroom. The names of the student will define a microstate because in this case there are many configurations.

a. A list of the names of each student present today. (microstate)

b. The number of students in attendance. (macrostate)

6 0
3 years ago
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