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3 years ago

The weather is warm and dry. Which change would a cold front bring?

Physics

2 answers:

astra-53 [7]3 years ago

8 0

Answer:

im prob too late lol but the answer would be rain or thunderstorms

Explanation:

i took the test :p

andreev551 [17]3 years ago

3 0

Answer:

rain or thunder

Explanation:

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Example of natural frequency

Verizon [17]

Natural frequency is a frequency when an object hits a s surface and causes ripples or vibrations or disturbance of their nearby source. An example is throwing a stone to water. When you throw a stone, it creates a wave around the fallen stone. The water is being disturbed by the stone and creates a wave. This is a natural frequency.

7 0

4 years ago

The power of a bulb is 100 watt .what does it mean

natita [175]

Answer:

Explanation: 100 watts is a unit of power.

A watt is also the amount of energy being consumed. So the more watts the brighter the light bulb is lit.

3 0

3 years ago

If a negatively charged rod touches a conductor, the conductor will be charged by what method?

musickatia [10]

b friction

thanks for the points

6 0

4 years ago

Read 2 more answers

A spherical raindrop 2.5 mm in diameter falls through a vertical distance of 3900 m. Take the cross-sectional area of a raindrop

Karolina [17]

Answer:

276.62 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 3900+0^2}\\\Rightarrow v=276.62\ m/s$

<u>Neglecting air drag</u> the velocity of the spherical drop would be 276.62 m/s

5 0

4 years ago

I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

$a_y$ = Acceleration in y axis = $9.81\ \text{m/s}^2$

$u_y$ = Initial velocity in y axis = 0

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$

Resultant velocity is given by

$v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}$

The fish is moving at a velocity of 28.1 m/s when it hits the water.

6 0

3 years ago