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1 year ago

12) Use the graph to estimate the X and Y intercepts:

Mathematics

1 answer:

Arturiano [62]1 year ago

8 0

Answer: X intercept = 18 Y intercept = 16

Step-by-step explanation: It appears that the line crosses x = 0 at 16 and y = 0 at 18

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Aidan and ethan were solving math problems together for homework adian did 410×10 to the fourth power would have 4 zeros in the

agasfer [191]

Answer:

No.

Step-by-step explanation:

410•10=4100 and 4100=41•100. We just need to focus on the 100. 100•100•100•100=100,000,000 which has 8 zeros, not 4 zeros.

7 0

3 years ago

If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun

saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

$P(t)=181843(1.04)^{(\frac{t}{10})}$

where, P(t) is population after t years.

At t=5,

$P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20$

At t=6,

$P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95$

At t=7,

$P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57$

At t=8,

$P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06$

At t=9,

$P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44$

At t=10,

$P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72$

The rate of change of P(t) on the interval $[x_1,x_2]$ is

$m=\frac{P(x_2)-P(x_1)}{x_2-x_1}$

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

$m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504$

The average rate of change of the population on the intervals [ 5 , 9 ] is

$m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06$

The average rate of change of the population on the intervals [ 5 , 8 ] is

$m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62$

The average rate of change of the population on the intervals [ 5 , 7 ] is

$m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185$

The average rate of change of the population on the intervals [ 5 , 6 ] is

$m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75$

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0

4 years ago

A ramp leading into a building makes a 15o angle with the ground. The end of the ramp is 10 feet from the base of the building.

Allushta [10]

Pls. see attachment. I drew my answer.

The ramp is approximately 10.40 feet long.

6 0

4 years ago

Read 2 more answers

Bárbara corre con rapidez constante de 5 km/h a lo largo de 500 m que separan el colegio de su casa. Demora 3 minutos en recoger

sergiy2304 [10]

Answer:

try socratic it should help

6 0

3 years ago

What is the value of x to the nearest tenth?

ryzh [129]

x is the radius of the circle. If we draw another radius to the end of the chord, we get a right triangle with legs 12 (half of 24) and 6, and hypotenuse x. We write the Pythagorean Theorem

$x^2 = 12^2 + 6^2 = 144 + 36 = 180$

$x = \sqrt{180} = \sqrt{36 \times 5} = 6 \sqrt{5}$

I don't like the calculator part; why ruin a nice exact answer with an approximation? But for completeness

$x \approx 13.4$

5 0

3 years ago