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nlexa [21]
1 year ago
10

Find from first principles the derivative of f:x maps to (x+2)all squared

Mathematics
1 answer:
Alik [6]1 year ago
7 0

Given:

f(x)=(x+2)^2

Required:

To find the first principles

Explanation:

First principle,

\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{(x+h+2)^2-(x+2)^2}{h}=\lim_{h\to0}\frac{x^2+(h+2)^2+2x(h+2)-x^2-4-4x}{h}=\lim_{h\to0}\frac{h^2+4+4h+2xh+4x-4-4x}{h}\begin{gathered} =\lim_{h\to0}\frac{h^2+4h+2xh}{h} \\  \\ =\lim_{h\to0}\frac{h(h+4+2x)}{h} \\  \\ =\lim_{h\to0}(h+4+2x) \\ =2x+4 \end{gathered}

Final Answer:

2x+4

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