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nlexa [21]
1 year ago
10

Find from first principles the derivative of f:x maps to (x+2)all squared

Mathematics
1 answer:
Alik [6]1 year ago
7 0

Given:

f(x)=(x+2)^2

Required:

To find the first principles

Explanation:

First principle,

\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{(x+h+2)^2-(x+2)^2}{h}=\lim_{h\to0}\frac{x^2+(h+2)^2+2x(h+2)-x^2-4-4x}{h}=\lim_{h\to0}\frac{h^2+4+4h+2xh+4x-4-4x}{h}\begin{gathered} =\lim_{h\to0}\frac{h^2+4h+2xh}{h} \\  \\ =\lim_{h\to0}\frac{h(h+4+2x)}{h} \\  \\ =\lim_{h\to0}(h+4+2x) \\ =2x+4 \end{gathered}

Final Answer:

2x+4

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\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

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METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

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