<span>Given that the
equation T^2=A^3 shows the relationship between a planet’s orbital
period, T, and the planet’s mean distance from the sun, A, in
astronomical units, AU.
i.e.

If planet Y is twice the mean distance from the
sun as planet X,
i.e.

,
then,

Therefore, the orbital period increased by a factor of 2^3/2</span>
Answer:
x => y
0 => 0
2 => 3
4 => 6
-2 => -3
Step-by-step explanation:
The equation of a proportional relationship is represented as y = kx,
where, k = y/x
We are given that k = ³/2
This means that, equation of the relationship therefore would be:
y = ³/2x
Use this equation to solve for each missing value on the table given:
✔️Where, y = 0, substitute y = 0 into y = ³/2x to find x:
0 = ³/2x
0 * 2 = 3x
0 = 3x
0/3 = x
x = 0
✔️Where, x = 2, substitute x = 2 into y = ³/2x to find y:
y = ³/2(2)
y = 3
✔️Where, y = 6, substitute y = 6 into y = ³/2x to find x:
6 = ³/2x
6 * 2 = 3x
12 = 3x
12/3 = x
x = 4
✔️Where, x = -2, substitute x = -2 into y = ³/2x to find y:
y = ³/2(-2)
y = -3
Answer:
$66.63
Step-by-step explanation:
6.5 * 10.25 = 66.625 = 66.63
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