Answer:
The correct options are;
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A
Step-by-step explanation:
Here we have for City A
Maximum - Minimum = 10
Interquartile range =3
City B
Maximum - Minimum = 18.5
Interquartile range =9.5
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.
You can have flash cards. Put a number on them and give at least 10 people a number and to do that close your eyes and pick 10 people. Now shuffle your flash cards up. Oh, yeah, and you don't have you give them a number in person, like find a picture of smokers and non-smokers and tape a number on your computer on the spot of their shirt. So shuffle the cards and pick 5 of the numbers now you're done!
3 small notebooks and 3 large ones
My reasoning is 3 times 7 is 21
63 - 21 = 42
3 times 14 is 42
So 42 + 21 = 63
Therefore 3 small and 3 large
The inequality that matches the graph would be C. -3x + 2y ≥ 7.
