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ale4655 [162]
1 year ago
8

For a population with a mean of u = 40 and a standarddeviation of o = 8, find the z-score corresponding toeach of the following

samples.a. X = 34 for a sample of n = 1 scoreb. x = 34 for a sample of n = 4 scoresc. x = 34 for a sample of n = 16 scores
Mathematics
1 answer:
ivann1987 [24]1 year ago
5 0

Solution:

Given the mean and standard deviation;

\mu=40,\sigma=8

The z-score formula is;

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

(a)

\begin{gathered} x=34,n=1 \\  \\ z=\frac{34-40}{\frac{8}{\sqrt{1}}} \\  \\ z=-0.75 \end{gathered}

(b)

\begin{gathered} x=34,n=4 \\  \\ z=\frac{34-40}{\frac{8}{\sqrt{4}}} \\  \\ z=-1.5 \end{gathered}

(c)

\begin{gathered} x=34,n=16 \\  \\ z=\frac{34-40}{\frac{8}{\sqrt{16}}} \\  \\ z=-3 \end{gathered}

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12 are tankesr
40 cars total
12/40
12/40=6/20=3/10

3/10=tankders
10/10-3/10=7/10
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3 0
3 years ago
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
3 years ago
Celeste started a new job with $500 in her account. after 50 hours of work, she deposits her pay check and she has $1500.
vovikov84 [41]

Answer:

$20 per hour

Step-by-step explanation:

1500 - 500 = 1000

1000 divided by 50 = 20

To check:

20 x 50 = 1000

7 0
3 years ago
Write an equation perpendicular to y= 1 -x+ 9 that passes through the point (-2,-2). 5​
lukranit [14]

<u>ANSWER</u><u> </u><u>:</u><u> </u>Hii friends follow me and give me brainliest ok by

6 0
3 years ago
(Will mark brainest)If it rains tomorrow the probability is 0.6 that James will practice piano. if it doesn't rain tomorrow ther
sergiy2304 [10]

Answer:

0.64

Step-by-step explanation:

P(J / R) = P (J and R) / P(R) 

0.8 = P (J and R) / 0.6 

P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] 

P(J / NR) = P (J and NR) / P(NR) 

0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 

P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] 

Hence; 

Probability of John practicing regardless of weather condition is 

P(John Practicing) = 0.48 + 0.16 = 0.64

HOPE THIS HELPED!!!

7 0
3 years ago
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