Answer:
Accelerating to top speed, deaccelerating to finish line.
Step-by-step explanation:
If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:
This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.
C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
Answer:
Correct option: second one
Step-by-step explanation:
Let's check each option to find the correct one.
First option: x and y increase by 2.3 times, so the figure expands. So this is not the correct option.
Second option: x and y decrease 0.52 times, so the figure is reduced. So this is the correct option.
Third option: x and y are translated by 1/3 of their position, so the figure is not reduced.
Fourth option: x and y increase by 7/2 times, so the figure expands. So this is not the correct option.
Correct option: second one
Answer:
squre root 32
Step-by-step explanation:
Step-by-step explanation:
-5(p + 3/5 ) = -4
-5p - 3/5 *5 = -4
-5p - 3 = - 4
-5p = -4 +3
-5p = -1
therefore p = 1/ 5
