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alina1380 [7]
1 year ago
11

If x is the midpoint of SP, SX = 42 AND XP =5X+8, WHAT IS X?

Mathematics
1 answer:
tigry1 [53]1 year ago
6 0

Answer:

x= 34/5 = 6.8

Step-by-step explanation:

Given  "<u>x is the midpoint of SP</u>" we can conclude that SX = XP since by the <u>midpoint definition</u> we know that X is dividing the line SP in congruent lines SX and XP.

Given "<u>SX = 42 AND XP =5X+8</u>" and that <u>SX = XP</u>, we can conclude that 5x+8 = 42.

Solve the equation to find the value of x:

5x +8 = 42, subtract 8 from both sides

5x +8 -8 = 42-8, combine like terms

5x = 34, divide both sides by 5

x= 34/5 = 6.8

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3 years ago
Whats the answer for 6b+7-2b=1+5b
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Solution,6b+7-2b=1+5b\quad :\quad b=6

Steps:

6b+7-2b=1+5b

\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b

\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7

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\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}

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\mathrm{The\:Correct\:Answer\:is\:b=6}

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An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that
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Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean,\mu=402.7 g

Standard deviation, \sigma=8.8g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})

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P(x>405.5)=0.022216

Hence, option b is correct.

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