The length of a rectangle is 4 less than three times it’s width. The perimeter is 72 feet. Find the dimensions of a rectangle

Mathematics

1 answer:

ratelena [41]3 years ago

6 0

Answer:

Step-by-step explanation:

so let’s say x is the length. Then the width will be 3x-4. You add them together and multiply by two. The perimeter is 72 so the equation equala 72.

Equation:

(x+3x-4)*2=72

(4x-4)*2=72

8x-8=72

8x=80

x=10

length:10

width:26

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Alex Ar [27]

Start by distributing the exponent to each of the terms in $(2u)^{3}$ . This will become $2^{3} u^{3}$ , and $2^{3} =8$ . Now, the expression is:

$\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }$ .

We can now simplify the bottom to read: $8u^{5}$ because when multiplying variables raised to an exponent, we add the exponents. The expression now looks like:

$\frac{2u^{3} v^{2} }{8u^{5} }$

The 2/8 simplifies to 1/4:

$\frac{u^{3} v^{2} }{4u^{5} }$

Now, we have two u terms on the top and bottom. When dividing variables raised to an exponent, we subtract the exponents. However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent. The final answer is:

$\frac{v^{2} }{4u^{2} }$