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polet [3.4K]
2 years ago
15

Does anyone know #4?

Mathematics
1 answer:
Marta_Voda [28]2 years ago
7 0

The state should charge rain tax for businesses that cause most environmental damage due to runoff from their paved areas

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6 divided by 2 (1+2)
user100 [1]
Observe. 

6/2(1+2)
6/2(3)
6/6
1

Thus, the answer is: 1

4 0
3 years ago
Read 2 more answers
Hey guys i ave nothing to do so can we have a conversation please
Kruka [31]
Sure I got time uh I’m not good at conversation starting but if you like anime I can talk about that for a long time but if I stop responding I’m probably doing homework
3 0
2 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
What is a good estimate for 470​% of 40​? Explain.
Harlamova29_29 [7]

Answer:

470% is equivalent to the decimal 4.7, which can be rounded to 5

So, 470% of 40 is approximately equal to 5 times 40

which is equal to 200

So, a good estimate for 470​% of 40 is 200.

4 0
2 years ago
5.796 is 9.2% of what number?
abruzzese [7]

Answer:

63

Step-by-step explanation:

5.796 / 0.092 = 63

8 0
3 years ago
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