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11Alexandr11 [23.1K]
1 year ago
4

Dr

Chemistry
1 answer:
kvasek [131]1 year ago
5 0
The i was a bit worried that the game was gonna be a bit boring and i was just
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N2 + 3H2 2NH3 How many molecules of H2 are represented in the reaction? How many nitrogen atoms are represented in the reactants
Tanzania [10]
There are 3 molecules of H2.
There are 2 atoms of nitrogen presented in the reactants.
2 moles of NH3 are formed.
4 0
3 years ago
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Aside from direct harm, what secondary issue do invasive species present?
solniwko [45]

Answer:

B

Explanation:

6 0
3 years ago
Which of the following is not true about limiting and excess reagents?
Bogdan [553]

Answer : The incorrect option is, (d) The reactant that was the smallest given mass is the limiting reagent.

Explanation :

Limiting reagent : It is the reagent that is completely consumed in the chemical reaction when the chemical reaction is complete. No amount is left after the reaction is complete. The amount of product obtained is determined by the limiting reagent. A balanced equation is necessary to determine which reactant is limiting reagent.

Excess reagent : It is the reagent that are not completely consumed in the chemical reaction. That means the reagent is in excess amount. Some amount of the excess reagent is left over after the reaction is complete.

From this we conclude that the options, A, B and C are correct. While the option D is incorrect.

Option D is incorrect because it is not necessary the reactant that was the smallest given mass is the limiting reagent but it is judge by the number of moles present in the reaction.

Hence, the incorrect option is, (d)

4 0
3 years ago
Can some one help with this question too??
ira [324]
Your answer is right tho
7 0
3 years ago
a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.
Alex17521 [72]

Answer:

m_{Co}=6998g=7.0kg

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})

Thus, we solve for the mass of cobalt as shown below:

m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg

Best regards!

7 0
3 years ago
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