All categories

3 years ago

Which of the following is not true about limiting and excess reagents?

Chemistry

1 answer:

Bogdan [553]3 years ago

4 0

Answer : The incorrect option is, (d) The reactant that was the smallest given mass is the limiting reagent.

Explanation :

Limiting reagent : It is the reagent that is completely consumed in the chemical reaction when the chemical reaction is complete. No amount is left after the reaction is complete. The amount of product obtained is determined by the limiting reagent. A balanced equation is necessary to determine which reactant is limiting reagent.

Excess reagent : It is the reagent that are not completely consumed in the chemical reaction. That means the reagent is in excess amount. Some amount of the excess reagent is left over after the reaction is complete.

From this we conclude that the options, A, B and C are correct. While the option D is incorrect.

Option D is incorrect because it is not necessary the reactant that was the smallest given mass is the limiting reagent but it is judge by the number of moles present in the reaction.

Hence, the incorrect option is, (d)

You might be interested in

A sample of CO2 weighing 86.34g contains how many molecules?

irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

86.34 g CO₂

Step 2: Identify Conversion

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

$86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} )$ = 1.18141 × 10²⁴ molecules CO₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0

3 years ago

A scientist finds that one volume of an unknown gas X combines with two volumes of another gas Y to form two volumes of a new ga

MariettaO [177]

Answer:

Gas X

Explanation:

The given reaction can be written in the form of chemical equation as shown below as:

$X+2Y\rightarrow 2XY_2$

According to law of conservation of mass, the moles of each substance in the reaction must be equal on both reactant and product side.

Also, the question asks for the gas which is diatomic. $XY_2$ cannot be diatomic as the formula contains 3 atoms.

Between gas X and gas Y , X has to be diatomic for the reaction to balance as:

$X_2+2Y\rightarrow 2XY_2$

3 0

3 years ago

(ill give brainliest)

gizmo_the_mogwai [7]

Answer:

It is because the object that is charged attracts the uncharged because it is giving electrons and passing it on to the object. As shown in the image the balloon is attracting the paper that is not charged. Actually telling,the charged object will cause the uncharged object to become charged, with a positive charge on one side and a negative charge on the other side. This process is called induction.

Explanation: Pls Mark Brainliest

4 0

2 years ago

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)

stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of O₂(g) produces 3 moles of CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1 : 3

What about ;

? (x) : 1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 : 3

What about

? (x) : 1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

#LearnWithBrainly

7 0

2 years ago

Am I correct ! Please tell me. If not then pls correct ! Thanks

scZoUnD [109]

Cu + 2H2SO4 ⟶ CuSO4 + SO2 + 2H20

In left hand side of the equation.

Cu = 1 atom

H = 4 atoms

S = 2 atoms

O = 8 atoms

In right hand side of the equation.

Cu = 1 atom

S = 2 atoms

0 = 8 atoms

H = 4 atoms

• All the atoms are balanced in the left and right side of the equation and it satisfies the law of conservation of mass.

• Equation is balanced and correct.

*See the attachment .

3 0

2 years ago