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Setler79 [48]
3 years ago
8

a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.

1 C. the final temperature of the water/cobalt mixture was 67.1 C. what was the mass of the sample of cobalt? ( Hint 1 mL of water has a mass of 1 gram)
Chemistry
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

m_{Co}=6998g=7.0kg

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})

Thus, we solve for the mass of cobalt as shown below:

m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg

Best regards!

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