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QveST [7]
3 years ago
14

6b Which of the following is a starting compound during cellular respiration?

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0

Answer: Oxygen and glucose.

Explanation:

Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.Jun 1, 2020

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Before you can find the mass, what do you need<br> to know?
Dmitrij [34]

Answer:The easiest way to find the mass of anything is to weigh it. You're actually measuring the force of gravity on the object, and technically, you should divide the weight by the acceleration due to gravity to get the mass.

Explanation:

3 0
3 years ago
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A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)
miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)  

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em>Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V</em>

<em>Zn²⁺(⁺aq) + 2 e⁻ → Zn(s)    E°red = -0.76 V</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

5 0
3 years ago
There are some exceptions to the trends of first and successive ionization energies. For each of the following pairs, explain wh
NNADVOKAT [17]

Answer:

(b) IE₂ of Ga >  IE₂ of Ge

Explanation:

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Electronic configuration of Ge is [Ar] 3d¹⁰4s²4p²

After 1st ionisation , Ga  becomes [Ar] 3d¹⁰4s² and becomes stable . Its

2 nd ionisation requires higher amount of ionisation energy. In case of Ge , there are 2 electrons in outermost orbital so it becomes stable after ionisation of 2 electrons.

4 0
3 years ago
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A pure substance made up of molecules of the same kind of atoms is called...
slava [35]

Answer:

All substances that are  made up of the same kind of mole ules are called pure substances.

So what do you mean ?

Explanation:

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Movement of electrons about a central nucleus is a concept by whom?
Alenkasestr [34]
The answer is bohr hope this helps :)
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