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Scorpion4ik [409]
3 years ago
9

Let f(x) = 9x - 4.5. Find the value of f(2).

Mathematics
2 answers:
defon3 years ago
7 0
9(2)-4.5=13.5 i think
wel3 years ago
4 0
<span>f(x) = 9x - 4.5
Substitute 2 for x
f(2) = 9(2) - 4.5
Multiply 9 by 2
f(2) = 18 - 4.5
Subtract
Final Answer: f(2) = 13.5</span>
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4r+9r-11r+7r= Simplify Combine like terms
Veseljchak [2.6K]

Answer:

9r

Step-by-step explanation:

4r+9r-11r+7r

Combine like terms

13r -11r+7r

2r+7r

9r

3 0
3 years ago
Read 2 more answers
AB= 4x + 7 and BC = 20x - 5 <br> AB ~= BC
Mariana [72]

The value of the variable x is 3/4

<h3>What are congruent segments</h3>

Congruent segment are segments with equal or congruent lengths.

From the information given, we have that line AB is approximately equal to line BC. This is represented as;

AB = BC

Where;

  • AB = 4x + 7
  • BC = 20x - 7

Now, let's equate the expressions

4x + 7 = 20x - 5

collect like terms

4x - 20x = - 5 - 7

- 16x = - 12

Make 'x' the subject of formula

x = -12/-16

x = 3/4

Thus, the value of the variable x is 3/4

Learn more about line segments here:

brainly.com/question/1388250

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8 0
2 years ago
Read 2 more answers
How many rational numbers lie between-2/3 and 7/3​
tiny-mole [99]

Answer:

infinite

Step-by-step explanation:

name two, and then find a third in between them.

you can repeat that as often as you want.

3 0
3 years ago
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Greatest to least: 17/20, 19/20, 0.19, 0.24
Yakvenalex [24]
19/20,17/20,0.24,0.19
5 0
3 years ago
The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

  • Minimum: 24.
  • Lower quartile: 29.
  • Median: 43.
  • Upper quartile: 50.
  • Maximum: 56.
  • Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

  • The minimum value is the smallest value, of 24.
  • The maximum value is the smallest value, of 56.
  • Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.
  • The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.
  • The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.
  • The interquartile range is of 50 - 29 = 21.

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