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Stolb23 [73]
1 year ago
14

Please answer this is only algebra 1

Mathematics
1 answer:
Alexeev081 [22]1 year ago
6 0

The numeric values for the given functions are as follows:

  • f(1/3) = 1/9.
  • g(4) = 8.
  • g(-3) = -6.

<h3>How to find the numeric value of a function or of an expression at a given point?</h3>

To find the numeric value of a function at x = a, we replace each instance of the variable, usually x, in the function by the desired value of a.

Function f(x) is defined by:

f(x) = x².

For the numeric value at x = 1/3, we replace the lone instance of x by 1/3, hence:

f(1/3) = (1/3)² = 1/9.

Function g(x) is defined by:

g(x) = 2x.

For the numeric value at x = 4, we replace the lone instance of x by 4, hence:

g(4) = 2(4) = 8.

For the numeric value at x = -3, we replace the lone instance of x by -3, hence:

g(-3) = 2(-3) = -6.

More can be learned about the numeric values of a function at brainly.com/question/28367050

#SPJ1

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8 0
2 years ago
Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. what is the value of c in her equation
Masteriza [31]

Answer:

Final answer is c=-7.

Step-by-step explanation:

Given equation is 0=-x^2+4x-7.

Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.

We know that standard form of quadratic equation is given by ax^2+bx+c=0.

compare given equation with the standard form, we find that -7 is written in place of +c

so that means +c=-7

or c=-7

Hence final answer is c=-7.

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