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Korvikt [17]
3 years ago
7

Describe the error in factoring the polynomial.

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

B:Multiplication of the outer terms of the two factors does not result in -7x

Step-by-step explanation:

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claudia bought a television at a 25% discount . the original price of the television was $349. there wasa 7% sales tax. how much
Scrat [10]
349 * .75 = $261.75
$261.75 * 1.07 = $280.07
6 0
3 years ago
Can someone help me with this?
Gre4nikov [31]
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3 years ago
Read 2 more answers
Solve for m GHI if m GHJ = 59° and m JHI = 39º.
Setler79 [48]

Answer:

m GHI = 82°

Step-by-step explanation:

59+39=98

180-98=82 <==== answer

180 is the total amount of degree

7 0
3 years ago
A rectangular prism measures 3ft by 6ft by 5ft. If the dimensions of the box were all quadrupled. How would the surface area of
Blababa [14]

The surface area of a shape is the amount of space on the shape

When the dimensions are quadrupled, the new surface area would be 16 times the initial surface area

<h3>How to determine the surface area</h3>

The surface area of a rectangular prism is:

S = 2 * (lw + lh + wh)

When quadrupled, we have:

S_2 = 2 * (16lw + 16lh + 16wh)

Factor out 16

S_2 =16 * 2 * (lw + lh + wh)

Substitute S = 2 * (lw + lh + wh)

S_2 =16 * 2 * S

The above means that:

The new surface area would be 16 times the initial surface area

Read more about surface areas at:

brainly.com/question/24571594

3 0
2 years ago
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

__

b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
3 years ago
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