6 i believe but im not sure
Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Answer:
(-5,10)
Step-by-step explanation:
What you can do in this case is the following rule of three to find the result:
1 light year ---> 5.88 * 10 ^ 12 miles
3.2 * 10 ^ 2 light year ---> x
Clearing x we have:
x = ((3.2 * 10 ^ 2) / (1)) * (5.88 * 10 ^ 12)
x = 1.88 * 10 ^ 15 miles
answer:
In scientific notation, approximately it is 1.88 * 10 ^ 15 miles
Step-by-step explanation:
<h3> a) [ -6 +22 – 6 + 8 ] ÷ ( -9 )</h3>
[ -6 +22 – 6 + 8 ] = 18
18 ÷ (-9) = -2
<h3> b) 400 ÷ { 40 – (-2) -3 – ( -1)} </h3>
{40 – (-2) -3 – ( -1)} = { 40 + 2 -3 + 1} = 40
400 ÷ 40 = 10
<h3>c) 40 x -23 + 40 x -17 </h3>
(40 x 23) + (40 x -17)
920 + (-680)
= 240
<h3>d) 1673 x 99 – (-1673) </h3>
(1673 x 99) + 1673
1673 x 100
= 167300
<h3>e) 490 x 98 = 48020</h3>
Hope this helps ^-^
