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Gelneren [198K]
3 years ago
14

7 ounce- 4.58$ 15 ounce- 6.30$ Find the unit rate of both numbers

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer:

7 ounces-4.58 = 1 ounce-0.654....

15 ounces-6.30= 1 ounce- 0.42

Explanation:

Divide 4.58 and 7 and divide 6.30 and 15.

And you get your answers.

I think im not really good with unit rate.

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Given the function g(x)=−2x−8, evaluate g(0).
Vera_Pavlovna [14]

Answer:

g(0) = -8

Step-by-step explanation:

When you plug in a zero for the x the equation will look like

g(0) = -2(0) - 8

-2 times 0 = 0 so g(0) = -8

7 0
2 years ago
CAn y’all PLEASEEEEE help me?
Nimfa-mama [501]

Answer:

option A is correct answer......

6 0
2 years ago
Read 2 more answers
Part A: Joel uses the incorrect expression 0.95(190)(0.8) to calculate that the computer will cost him a total of $144.40. Descr
UkoKoshka [18]

Complete question:

Joelwants to buy a new tablet computer from a store having a 20% off sale on all tablet. The tablet he wants has an original cost of $190. He also wants to make sure he has enough money to pay the 5% sales tax.

Answer:

$159.60

Step-by-step explanation:

Given the following :

Sales tax = 5%

Percentage discount = 20%

Original cost = $190

Joel's incorrect expression : 0.95(190)(0.8)

Joel's mistake is the 0.95 which is equivalent to 95% used in Calculating the total cost of the computer. The sales tax increases the total cost of the computer and instead of subtracting 5% sales tax, it should be added.

B.) 20% discount = 0.2 will be deducted from 100%(1)

1 - 0.2 = 0.8

5% sales tax = 0.05 will be added :

1 + 0.05 = 1.05

Original cost = $190

Therefore,

Total cost : Original cost * sales tax * discount

Total cost = $190 * 1.05 * 0.8

Total cost = $159.60

6 0
3 years ago
Solve this @ineedhelplsss
Brut [27]
4^2(x+6)^2-6^2=4x-6+2x^2\ \ \ |use\ (a+b)^2=a^2+2ab+b^2\\\\16(x^2+12x+36)-36=4x-6+2x^2\\\\16x^2+192x+576-36=4x-6+2x^2\\\\16x^2-2x^2+192x-4x+540+6=0\\\\14x^2+188x+546=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\7x^2+94x+273=0\\\\a=7;\ b=94;\ c=273\\\Delta=b^2-4ac\to\Delta=94^2-4\cdot7\cdot273=8836-7644=1192 \ \textgreater \  0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1192}=\sqrt{4\cdot298}=\sqrt4\cdot\sqrt{298}=2\sqrt{289}

x_1=\dfrac{-94-2\sqrt{298}}{2\cdot7}=\dfrac{-47-\sqrt{298}}{7}\\\\x_2=\dfrac{-94+2\sqrt{298}}{2\cdot7}=\dfrac{-47+\sqrt{298}}{7}
8 0
3 years ago
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